Введение в модель данных SQL



Пример 16.5


WITH RECURSIVE PARTS (PART_NUMBER, NUMBER_OF_PARTS, COST) AS (SELECT CONTAINED_PART, 1, 0.00 FROM CAR WHERE CONTAINING_PART = '' UNION ALL SELECT CAR.CONTAINED_PART, CAR.NUMBER_OF_PARTS, CAR.NUMBER_OF_PARTS * CAR.PART_COST FROM CAR, PARTS WHERE PARTS.PART_NUMBER = CAR.CONTAINING_PART) CYRCLE CONTAINED_PART SET CYCLEMARK TO 'Y' DEFAULT 'N' USING CYRCLEPATH SELECT PART_NUMBER, SUM(NUMBER_OF PARTS), SUM(COST) FROM PARTS ORDER BY PART_NUMBER;

Пример 16.5.

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